If cos^(-1)sin⁡x≥sin^(-1)sin⁡x, then the number of integral values of x in the interval x∈0,3π are

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MARKS Content Team · Accepted Answer

Correct answer: (D) 5. If cos^(-1)x≥sin^(-1)x, then x∈-1/(√2),1/(√2) {using graph} For given inequality, we must have sin⁡x∈-1√2,1√2 ⇒x∈nπ-(π)/4,nπ+(π)/4,n∈Ι Possible integral values of x are 0,3,6,7,9

If $c o s^{- 1} |\sin x| \geq s i n^{- 1} |\sin x|$ , then the number of integral values of $x$ in the interval $x \in [0,3 π]$ are

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More Inverse Trigonometric Functions Questions

If cos-1sin⁡x≥sin-1sin⁡x, then the number of integral values of x in the interval x∈0,3π are

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More Inverse Trigonometric Functions Questions

If $c o s^{- 1} |\sin x| \geq s i n^{- 1} |\sin x|$ , then the number of integral values of $x$ in the interval $x \in [0,3 π]$ are