Q121 / 180 · KCET 2011 · Physics

If $C$ be the capacitance and $V$ be the electric potential, then the dimensional formula of $C V^{2}$ is

  • Correct answer
    A
    $\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{0}\right]$
  • B
    $\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-1}\right]$
  • C
    $\left[\mathrm{M}^{0} \mathrm{LT}{ }^{2} \mathrm{~A}^{0}\right]$
  • D
    $\left[\mathrm{ML}{ }^{3} \mathrm{TA}\right]$

Solution

We know, Energy, $E=C V^{2}$ Dimensions of $C V^{2}=$ Dimensions of energy $$ =\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right] $$

Hence, the correct answer is option: 'A'.

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