Q121 / 180 · KCET 2011 · Physics
If $C$ be the capacitance and $V$ be the electric potential, then the dimensional formula of $C V^{2}$ is
- Correct answerA$\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{0}\right]$
- B$\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-1}\right]$
- C$\left[\mathrm{M}^{0} \mathrm{LT}{ }^{2} \mathrm{~A}^{0}\right]$
- D$\left[\mathrm{ML}{ }^{3} \mathrm{TA}\right]$
Solution
We know,
Energy, $E=C V^{2}$
Dimensions of $C V^{2}=$ Dimensions of energy
$$
=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]
$$
Hence, the correct answer is option: 'A'.