If $\bar{a}=\bar{i}-2 \bar{j}+2 \bar{k}, \bar{b}=6 \bar{i}+3 \bar{j}-2 \bar{k}, \bar{c}=-4 \bar{i}+3 \bar{j}+12 \bar{k}$ are three vectors then $\sqrt{(|\bar{a}|+|\bar{b}|+|\bar{c}|)+|\bar{a}+\bar{b}+\bar{c}|}=$

• A

  $13$
• B

  $13 \sqrt{10}$
• Correct answer
  C

  $6$
• D

  $10 \sqrt{3}$

Hence, the correct answer is option: 'C'.