Q48 / 160 · AP EAMCET 2003 · Mathematics
If $\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}, \overrightarrow{\mathbf{c}}$ are three vectors such that $\overrightarrow{\mathbf{a}}=\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}}$ and the angle between $\overrightarrow{\mathbf{b}}$ and $\overrightarrow{\mathbf{c}}$ is $\frac{\pi}{2}$, then:
- Correct answerA$a^2=b^2+c^2$
- B$b^2=c^2+a^2$
- C$c^2=a^2+b^2$
- D$2 a^2-b^2=c^2$
Solution
Given that $\overrightarrow{\mathbf{a}}=\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}}$

and $\overrightarrow{\mathbf{b}} \perp \overrightarrow{\mathbf{c}}$ then $(\overrightarrow{\mathbf{a}})^2=(\overrightarrow{\mathbf{b}})^2+(\overrightarrow{\mathbf{c}})^2$ $a^2=b^2+c^2$

and $\overrightarrow{\mathbf{b}} \perp \overrightarrow{\mathbf{c}}$ then $(\overrightarrow{\mathbf{a}})^2=(\overrightarrow{\mathbf{b}})^2+(\overrightarrow{\mathbf{c}})^2$ $a^2=b^2+c^2$
Hence, the correct answer is option: 'A'.