If $x_1, x_3$ are the roots of $A x^2-4 x+1=0$ and $x_2, x_4$ are the roots of $B x^2-6 x+1=0$ such that $x_1, x_2, x_3, x_4$ are in harmonic progression, then $\frac{B+A}{B-A}=$

• Correct answer
  A

  $\frac{11}{5}$
• B

  $\frac{-11}{5}$
• C

  $\frac{5}{11}$
• D

  $\frac{-5}{11}$

Hence, the correct answer is option: 'A'.