If $\mathrm{x}^2-4 \mathrm{ax}+5+\mathrm{a}>0$ for all $\mathrm{x} \in \mathrm{R}$ whenever $\mathrm{a} \in(\alpha, \beta)$, then $4 \beta+\alpha=$

• A

  $0$
• Correct answer
  B

  $4$
• C

  $5$
• D

  $8$

Hence, the correct answer is option: 'B'.