Q105 / 170 · Manipal (MET) 2019 · Mathematics
If $\mathbf{a}=-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-3 \hat{\mathbf{k}}$ and $\mathbf{c}=-4 \hat{\mathbf{i}}-\hat{\mathbf{k}}$, then $\mathbf{a} \times(\mathbf{b} \times \mathbf{c})+(\mathbf{a} \cdot \mathbf{b}) \mathbf{c}$
- Correct answerA$5 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}-15 \hat{\mathbf{k}}$
- B$0$
- C$12 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}$
- D$-3 \hat{\mathbf{i}}+6 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}$
Solution
$\begin{aligned} & \text { } \mathbf{a}=-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-3 \hat{\mathbf{k}} \\ & \mathbf{c}=-4 \hat{\mathbf{i}}-\hat{\mathbf{k}} \\ & \therefore \mathbf{a} \times(\mathbf{b} \times \mathbf{c})+(\mathbf{a} \cdot \mathbf{b}) \mathbf{c}=(\mathbf{a} \cdot \mathbf{c}) \mathbf{b} \\ & =(4+1)(\hat{\mathbf{i}}+\hat{\mathbf{j}}-3 \hat{\mathbf{k}})=5 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}-15 \hat{\mathbf{k}}\end{aligned}$
Hence, the correct answer is option: 'A'.