If $f(x)=x^2+b x+c$ and $f(1+k)=f(1-k) \forall \mathrm{K} \in \mathbb{R}$, for two real numbers b and c, then

• Correct answer
  A

  $f(1) < f(0) < f(-1)$
• B

  $f(-1) < f(0) < f(1)$
• C

  $f(0) < f(-1) < f(1)$
• D

  $f(0) < f(1) < f(-1)$

Hence, the correct answer is option: 'A'.