Q223 / 270 · NDA 2021 (Phase 1) · Mathematics
If $\vec{a}$ and $\vec{b}$ are two vectors such that $|\vec{a}+\vec{b}|=|\vec{a}-\vec{b}|=4$, then which one of the following is correct?
- A$\vec{a}$ and $\vec{b}$ must be unit vectors.
- B$\vec{a}$ must be parallel to $\vec{b}$.
- Correct answerC$\vec{a}$ must be perpendicular to $\vec{b}$.
- D$\vec{a}$ must be equal to $\vec{b}$.
Solution
$|\vec{a}+\vec{b}|=|\vec{a}-\vec{b}|$
On squaring both sides, we get
$|\vec{a}+\vec{b}|^2=|\vec{a}-\vec{b}|^2$
$|\vec{a}|^2+|\vec{b}|^2+2 \vec{a} \cdot \vec{b}=|\vec{a}|^2+|\vec{b}|^2-2 \vec{a} \cdot \vec{b}$
$\vec{a} \cdot \vec{b}=0 \quad \therefore \quad \vec{a} \perp \vec{b}$
Hence, the correct answer is option: 'C'.