Q142 / 160 · TS EAMCET 2024 (09 May Shift 1) · Physics

If a ray of light passes through an equilateral prism such that the angle of incidence and the angle of emergence are both equal to $70 \%$ of the angle of the prism, then the angle of minimum deviation is

  • A
    $36^{\circ}$
  • B
    $18^{\circ}$
  • C
    $42^{\circ}$
  • Correct answer
    D
    $24^{\circ}$

Solution

using $A+\delta=\mathbf{i}+e \Rightarrow \delta=\mathrm{i}+\mathrm{e}-\mathrm{A}$ Equilateral prism so $\mathrm{A}=60^{\circ}$ And $\mathrm{i}=\mathrm{e}=60^{\circ} \times \frac{70}{100}=42^{\circ}$ $\therefore \delta=42^{\circ}+42^{\circ}-60^{\circ}=24^{\circ}$

Hence, the correct answer is option: 'D'.

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