Q68 / 120 · VITEEE 2009 · Mathematics
If a line in the space makes angle $\alpha, \beta$ and $\gamma$ with the coordinate axes, then
$\begin{aligned}
\cos 2 \alpha+\cos 2 \beta+\cos 2 \gamma+\sin ^{2} \alpha+& \sin ^{2} \beta \\
+& \sin ^{2} \gamma \text { equals }
\end{aligned}$
- A$-1$
- B0
- Correct answerC1
- D2
Solution
$\cos 2 \alpha+\cos 2 \beta+\cos 2 \gamma$ $\quad+\sin ^{2} \alpha+\sin ^{2} \beta+\sin ^{2} \gamma$ $\quad\left(\cos ^{2} \alpha-\sin ^{2} \alpha\right)+\left(\cos ^{2} \beta-\sin ^{2} \beta\right)$ $\quad\left(\cos ^{2} \gamma-\sin ^{2} \gamma\right)+\sin ^{2} \alpha+\sin ^{2} \beta+\sin ^{2} \gamma$ $=\cos ^{2} \alpha+\cos ^{2} \beta+\cos ^{2} \gamma=1$
Hence, the correct answer is option: 'C'.