If $A, B$ and $C$ are square matrices of same order and $\mathrm{{\rm I}}$ is an identity matrix of the same order, such that $C^2=CB+AC$ and $AB=\mathrm{{\rm I}},$ then ${\left(C-A\right)}^{-1}$ is equal to

• A

  $C-A$
• Correct answer
  B

  $C-B$
• C

  $B-C$
• D

  $B+\mathrm{{\rm I}}$

Hence, the correct answer is option: 'B'.