If $P=\left[\begin{array}{cc}\lambda & 0\\ 1& 1\end{array}\right]$ and $Q=\left[\begin{array}{cc}4& 0\\ 3& 1\end{array}\right]$ such that $P^2=Q,$ then $P^3$ is equal to

• Correct answer
  A

  $\left[\begin{array}{cc}8& 0\\ 7& 1\end{array}\right]$
• B

  $\left[\begin{array}{cc}10& 1\\ 8& 0\end{array}\right]$
• C

  $\left[\begin{array}{cc}7& 0\\ 8& 1\end{array}\right]$
• D

  $\left[\begin{array}{cc}6& 0\\ 4& 1\end{array}\right]$

Hence, the correct answer is option: 'A'.