If a=∫01(cossin⁡x)/(sec⁡x)dx, then the value of a^2+cos^2sin⁡1 is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) 1. a=∫01cos⁡sin⁡xcos⁡xdx Let sin⁡x=t ⇒cos⁡xdx=dt ∴a=∫0sin⁡1cos⁡tdt=(sin⁡t)0sin⁡1 =sinsin⁡1-sin⁡0 =sinsin⁡1 ∴a^2+cos^2sin⁡1=sin^2⁡θ+cos^2⁡θ=1; θ=sin⁡1

If $a = \int_{0}^{1} \frac{c o s (\sin x)}{\sec x} d x,$ then the value of $a^{2} + {c o s}^{2} (\sin 1)$ is equal to

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More Definite Integration Questions

If a=∫01cossin⁡xsec⁡xdx, then the value of a2+cos2sin⁡1 is equal to

Solution

More Definite Integration Questions

If $a = \int_{0}^{1} \frac{c o s (\sin x)}{\sec x} d x,$ then the value of $a^{2} + {c o s}^{2} (\sin 1)$ is equal to