Q22 / 118 · NTA Abhyas (JEE Main) 2020 · Mathematics · Sequences and Series

If 2, h1, h2,....., h20, 6 are in harmonic progression and 2, a1, a2,...., a20, 6 are in arithmetic progression, then the value of a3h18 is equal to

  • A
    6
  • Correct answer
    B
    12
  • C
    3
  • D
    9

Solution

12,1h1,1h2,....,1h20,16 are in A.P.
⇒16=12+21d⇒16-1221=d
⇒d=-163
⇒1h18=12+18d=12+182-1637=12-27
1h18=314⇒h18=143
Also, 2,a1,a2,.....,a20,6 are in A.P.
⇒6=2+21D⇒D=421
⇒a3=2+3D=2+3×4217=187
⇒a3h18=1867×1423=12

Hence, the correct answer is option: 'B'.

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