Q72 / 90 · JEE Main 2019 (08 Apr Shift 1) · Physics

If 1022 gas molecules each of mass 10-26 kg collides with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed 104m/s, the pressure exerted by the gas molecules will be of the order of:

  • Correct answer
    A
     2 Pa
  • B
     4 Pa
  • C
     6 Pa
  • D
     8 Pa

Solution

Total momentum transferred in one second =n2mv=10222×10-26×104=2
Force experienced by surface =2 N
Pressure on surface =ForceArea=21=2 Pa

Hence, the correct answer is option: 'A'.

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