Q29 / 116 · NTA Abhyas (JEE Main) 2020 · Mathematics · Definite Integration

If ∫01x11e-x24dx=A, and ∫01x3e-x8dx=B, then the relation between A and B is

  • A
    A=3B
  • Correct answer
    B
    B=3A
  • C
    A+3B=0
  • D
    B+3A=0

Solution

In A, let x12=t
⇒12x11dx=dt
⇒A=112∫01e-t2dt
In B, let x4=u
⇒4x3dx=du
⇒B=14∫01e-u2dx=14∫01e-t2dt
⇒B=1412A⇒B=3A

Hence, the correct answer is option: 'B'.

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