Q32 / 150 · MHT CET 2026 (11 April Shift 1) · Chemistry
Identify the set of paramagnetic ions among the following.
- A$\text{V}^{+2}, \text{Co}^{+2}, \text{Ti}^{+4}$
- B$\text{Ni}^{+2}, \text{Cu}^{+2}, \text{Zn}^{+2}$
- Correct answerC$\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$
- D$\text{Sc}^{+3}, \text{Ti}^{+3}, \text{V}^{+3}$
Solution
Paramagnetic ions are those that contain at least one unpaired electron in their electronic configuration.
Writing the outer electronic configurations of the given ions:
$\text{V}^{+2}$: $[\text{Ar}] 3d^{3}$ (3 unpaired electrons, paramagnetic)
$\text{Co}^{+2}$: $[\text{Ar}] 3d^{7}$ (3 unpaired electrons, paramagnetic)
$\text{Ti}^{+4}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)
$\text{Ni}^{+2}$: $[\text{Ar}] 3d^{8}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Zn}^{+2}$: $[\text{Ar}] 3d^{10}$ (0 unpaired electrons, diamagnetic)
$\text{Ti}^{+2}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Mn}^{+3}$: $[\text{Ar}] 3d^{4}$ (4 unpaired electrons, paramagnetic)
$\text{Sc}^{+3}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)
$\text{Ti}^{+3}$: $[\text{Ar}] 3d^{1}$ (1 unpaired electron, paramagnetic)
$\text{V}^{+3}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)
The set containing only paramagnetic ions is $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$.
Answer: $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$
Writing the outer electronic configurations of the given ions:
$\text{V}^{+2}$: $[\text{Ar}] 3d^{3}$ (3 unpaired electrons, paramagnetic)
$\text{Co}^{+2}$: $[\text{Ar}] 3d^{7}$ (3 unpaired electrons, paramagnetic)
$\text{Ti}^{+4}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)
$\text{Ni}^{+2}$: $[\text{Ar}] 3d^{8}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Zn}^{+2}$: $[\text{Ar}] 3d^{10}$ (0 unpaired electrons, diamagnetic)
$\text{Ti}^{+2}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Mn}^{+3}$: $[\text{Ar}] 3d^{4}$ (4 unpaired electrons, paramagnetic)
$\text{Sc}^{+3}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)
$\text{Ti}^{+3}$: $[\text{Ar}] 3d^{1}$ (1 unpaired electron, paramagnetic)
$\text{V}^{+3}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)
The set containing only paramagnetic ions is $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$.
Answer: $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$
Hence, the correct answer is option: 'C'.