Q32 / 150 · MHT CET 2026 (11 April Shift 1) · Chemistry

Identify the set of paramagnetic ions among the following.

  • A
    $\text{V}^{+2}, \text{Co}^{+2}, \text{Ti}^{+4}$
  • B
    $\text{Ni}^{+2}, \text{Cu}^{+2}, \text{Zn}^{+2}$
  • Correct answer
    C
    $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$
  • D
    $\text{Sc}^{+3}, \text{Ti}^{+3}, \text{V}^{+3}$

Solution

Paramagnetic ions are those that contain at least one unpaired electron in their electronic configuration.

Writing the outer electronic configurations of the given ions:
$\text{V}^{+2}$: $[\text{Ar}] 3d^{3}$ (3 unpaired electrons, paramagnetic)
$\text{Co}^{+2}$: $[\text{Ar}] 3d^{7}$ (3 unpaired electrons, paramagnetic)
$\text{Ti}^{+4}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)

$\text{Ni}^{+2}$: $[\text{Ar}] 3d^{8}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Zn}^{+2}$: $[\text{Ar}] 3d^{10}$ (0 unpaired electrons, diamagnetic)

$\text{Ti}^{+2}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)
$\text{Cu}^{+2}$: $[\text{Ar}] 3d^{9}$ (1 unpaired electron, paramagnetic)
$\text{Mn}^{+3}$: $[\text{Ar}] 3d^{4}$ (4 unpaired electrons, paramagnetic)

$\text{Sc}^{+3}$: $[\text{Ar}] 3d^{0}$ (0 unpaired electrons, diamagnetic)
$\text{Ti}^{+3}$: $[\text{Ar}] 3d^{1}$ (1 unpaired electron, paramagnetic)
$\text{V}^{+3}$: $[\text{Ar}] 3d^{2}$ (2 unpaired electrons, paramagnetic)

The set containing only paramagnetic ions is $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$.

Answer: $\text{Ti}^{+2}, \text{Cu}^{+2}, \text{Mn}^{+3}$

Hence, the correct answer is option: 'C'.

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