Q68 / 90 · JEE Main 2024 (04 Apr Shift 2) · Physics

Identify the logic gate given in the circuit:

A
NAND-gate
B
AND gate
C
NOR gate
Correct answer
D
OR- gate

Solution

$\mathrm{Y}=\overline{\overline{\mathrm{A}} \cdot \overline{\mathrm{B}}}$
By De-Morgan Law $\begin{aligned} & \mathrm{Y}=\overline{\overline{\mathrm{A}+\mathrm{B}}} \\ & \mathrm{Y}=\mathrm{A}+\mathrm{B} \end{aligned}$
Hence OR gate

Hence, the correct answer is option: 'D'.

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