Q20 / 75 · JEE Main 2025 (28 Jan Shift 2) · Chemistry
Identify correct conversion during acidic hydrolysis from the following :
(A) starch gives galactose.
(B) cane sugar gives equal amount of glucose and fructose.
(C) milk sugar gives glucose and galactose.
(D) amylopectin gives glucose and fructose.
(E) amylose gives only glucose.
Choose the correct answer from the options given below :
- A(A), (B) and (C) only
- Correct answerB(B), (C) and (E) only
- C(C), (D) and (E) only
- D(B), (C) and (D) only
Solution
$(\mathrm{A})$ Starch $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
(B) Cane sugar $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ glucose + fructose (Sucrose) $50 \% \quad 50 \%$
(C) Milk sugar $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ glucose + galactose (Lactose)
(D) Amylopectin $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
(E) Amylose $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
So, correct options are B,C,and E only.
Hence, the correct answer is option: 'B'.