Q20 / 150 · MHT CET 2022 (05 Aug Shift 1) · Chemistry

How many mole of electron are required fro the reduction of 1 mole of $\mathrm{Cr}^3+$ to $\mathrm{Cr}_{(\mathrm{s})}$ ?

  • Correct answer
    A
    $3$
  • B
    $6$
  • C
    $1$
  • D
    $\frac{6.022 \times 10^{23}}{3}$

Solution

$\underset{1 \mathrm{mo1}}{\mathrm{Cr}^{+3}}+\underset{3 \mathrm{mo1}}{3 \mathrm{e}^{-}} \rightarrow \mathrm{Cr}(\mathrm{s})$

Hence, the correct answer is option: 'A'.

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