Graph betwen stopping potential for most energetic emitted photoelectrons $\left(\mathrm{V}_{\mathrm{s}}\right)$ with frequency (v) of incident radiation on metal is given below. Value of $\mathrm{AB} / \mathrm{BC}$, in graph is [where $\mathrm{h}=$ plank's constant, $\mathrm{e}=$ electronic charge]

• A

  $h$
• B

  e
• Correct answer
  C

  $\mathrm{h} / \mathrm{e}$
• D

  $\mathrm{e} / \mathrm{h}$

Hence, the correct answer is option: 'C'.