Q10 / 75 · JEE Main 2026 (23 January Shift 2) · Chemistry

Given below are two statements:
Statement I: $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ is more stable than $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ as nine hyperconjugation interactions are possible in $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$.
Statement II: $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ is less stable than $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ as only three hyperconjugation interactions are possible in $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$.
In the light of the above statements, choose the correct answer from the options given below

  • A
    Statement I is false but Statement II is true
  • Correct answer
    B
    Statement I is true but Statement II is false
  • C
    Both Statement I and Statement II are true
  • D
    Both Statement I and Statement II are false

Solution

Statement I: In the tert-butyl carbocation $(CH_3)_3C^+$, there are three methyl groups attached to the carbocationic carbon. Each methyl group has 3 $\alpha$-hydrogens, making a total of 9 $\alpha$-hydrogens. Thus, 9 hyperconjugation interactions are possible, which significantly stabilize the carbocation. Statement I is true.
Statement II: In the methyl carbocation $CH_3^+$, there are no $\alpha$-carbons and consequently no $\alpha$-hydrogens. Hyperconjugation requires the presence of at least one $\alpha$-hydrogen on a carbon adjacent to the $sp^2$ hybridized carbocation center. Therefore, zero hyperconjugation interactions are possible in $CH_3^+$. Statement II is false because it claims three hyperconjugation interactions are possible.
Conclusion: Statement I is true but Statement II is false.

Hence, the correct answer is option: 'B'.

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