From a point P on the circle $\mathrm{x}^2+\mathrm{y}^2=4$, two tangents are drawn to the circle $x^2+y^2-6 x-6 y+14=0$. If $A$ and $B$ are the points of contact of those lines, then the locus of the centre of the circle passing through the points $\mathrm{P}, \mathrm{A}$ and B is

• A

  $x^2+y^2-3 x-3 y+4=0$
• B

  $2 x^2+2 y^2+6 x+6 y-7=0$
• C

  $x^2+y^2+3 x+3 y-4=0$
• Correct answer
  D

  $2 x^2+2 y^2-6 x-6 y+7=0$

Hence, the correct answer is option: 'D'.