From a point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ if chords are drawn to this circle, then locus of the poles of these chords with respect the circle $x^2+y^2=4$ is

• Correct answer
  A

  $x=4$
• B

  $x+2 y=5$
• C

  $x^2+y^2-x-y=0$
• D

  $2 y^2=(x+1)$

Solution

Chord from point $(1,0)$ on the circle $x^2+y^2-2 x+2 y+1=0$ is polar on the circle $x^2+y^2=4$


So, locus of poles of the chords is equation of polar at $(1,0)$ on the circle $x^2+y^2=4$ i.e., $x=4$.

Hence, the correct answer is option: 'A'.