Q104 / 197 · NEET 2009 (Mains) · Physics

Four identical thin rods each of mass $M$ and length $l$, from a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is :

  • A
    $\frac{1}{3} \mathrm{M} l^2$
  • Correct answer
    B
    $\frac{4}{3} \mathrm{M} l^2$
  • C
    $\frac{2}{3} \mathrm{M} l^2$
  • D
    $\frac{13}{3} \mathrm{M} l^2$

Solution

$\quad I=4 \times\left[\frac{M \ell^2}{12}+M\left(\frac{\ell}{2}\right)^2\right]$ the parallel axis $$ \text { theorem }=\frac{4}{3} \mathrm{M} \ell^2 $$

Hence, the correct answer is option: 'B'.

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