Q157 / 160 · AP EAMCET 2022 (07 Jul Shift 2) · Physics
For the logic gates shown below, the correct output is


- A$A+B+C$
- B$\bar{A} \cdot \bar{B} \cdot \bar{C}$
- Correct answerC$\bar{A}+\bar{B}+\bar{C}$
- D$\overline{A \cdot B}+\overline{B \cdot C}$
Solution
For the logic gates shown below

The logic operation can be written as $$ \begin{aligned} & \overline{A \cdot A}+(\overline{A \cdot B}+\overline{B \cdot C}+\overline{B \cdot B} \\ & =\overline{A \cdot A}+\bar{A}+\bar{B}+\bar{B}+C+\overline{B \cdot B} \quad(\text { Note } \overline{A \cdot A}=\bar{A}) \\ & =\bar{A}+\bar{A}+\bar{A}+\bar{B}+\bar{B}+\bar{C}+\bar{B} \quad(\text { Note } \bar{A}+\bar{A}=\bar{A}) \\ & =\bar{A}+\bar{B}+\bar{C} \end{aligned} $$

The logic operation can be written as $$ \begin{aligned} & \overline{A \cdot A}+(\overline{A \cdot B}+\overline{B \cdot C}+\overline{B \cdot B} \\ & =\overline{A \cdot A}+\bar{A}+\bar{B}+\bar{B}+C+\overline{B \cdot B} \quad(\text { Note } \overline{A \cdot A}=\bar{A}) \\ & =\bar{A}+\bar{A}+\bar{A}+\bar{B}+\bar{B}+\bar{C}+\bar{B} \quad(\text { Note } \bar{A}+\bar{A}=\bar{A}) \\ & =\bar{A}+\bar{B}+\bar{C} \end{aligned} $$
Hence, the correct answer is option: 'C'.