Q22 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ then the input signal voltage is

  • A
    10  mV
  • Correct answer
    B
    20  mV
  • C
    30  mV
  • D
    15  mV

Solution

RC=2 kΩ     V0=4 V

IC=V0Rc=4 V2 kΩ=2 mA

β=ICIB=100

⇒IB=IC100=2×10-5 A

Vin=IBRi=2×10-5×1 kΩ=20 mV

Hence, the correct answer is option: 'B'.

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