Q21 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

For a transistor, the current amplification factor α  is 0.8. If it is connected in common emitter configuration, the change in collector current when the base current changes by 6 mA is

  • A
    6 mA
  • B
    4.8 mA
  • Correct answer
    C
    24 mA
  • D
    8 mA

Solution

Ic=α1-αIb=0.80.2Ib=4Ib

Ic=collector current
Ib=base current

Ic=24 mA

Hence, the correct answer is option: 'C'.

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