Q30 / 90 · JEE Main 2010 · Chemistry

For a particular reversible reaction at temperature $T, \Delta H$ and $\Delta S$ were found to be both $+v e$. If $T_e$ is the temperature at equilibrium, the reaction would be spontaneous when

  • A
    $T_e>T$
  • Correct answer
    B
    $\mathrm{T}>\mathrm{T}_{\mathrm{e}}$
  • C
    $T_e$ is 5 times $T$
  • D
    $T =T_e$

Solution

$$ \Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S} $$ at equilibrium, $\Delta \mathrm{G}=0$ for a reaction to be spontaneous $\Delta$ G should be negative $$ \therefore \mathrm{T}>\mathrm{T}_{\mathrm{e}} $$

Hence, the correct answer is option: 'B'.

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