For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:5 respectively. If the frequency of fifth harmonic is 405 Hz…

Question

For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:5 respectively. If the frequency of fifth harmonic is 405 Hz and the speed of sound in air is 324 m s^(–1) the length of the organ pipe is _____ m.

MARKS Content Team · Accepted Answer

Correct answer: 1. It is given, f_5=405 Hz. As the first three resonance frequencies are in the ratio of 1:3:5, therefore it must be a closed organ pipe. The frequency formula in a closed organ pipe is given by f=nv/4l. So, 5v/4I=405 Hz ⇒I=(405×4)/(5×324)=1 m

For a certain organ pipe, the first three resonance frequencies are in the ratio of $1 : 3 : 5$ respectively. If the frequency of fifth harmonic is $405 Hz$ and the speed of sound in air is $324 m s^{- 1}$ the length of the organ pipe is _____ $m$ .

Solution

Relevant Questions

For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:5 respectively. If the frequency of fifth harmonic is 405 Hz and the speed of sound in air is 324 m s–1 the length of the organ pipe is _____ m.

Solution

Relevant Questions

For a certain organ pipe, the first three resonance frequencies are in the ratio of $1 : 3 : 5$ respectively. If the frequency of fifth harmonic is $405 Hz$ and the speed of sound in air is $324 m s^{- 1}$ the length of the organ pipe is _____ $m$ .