Q123 / 160 · WBJEE 2011 · Physics
Five equal resistance, each of resistance \(\mathrm{R}\), are connected as shown in figure below. A battery of \(\mathrm{V}\) volt is connected between \(A\) and \(B\). The current flowing in \(\mathrm{FC}\) will be


- A\(\frac{3 \mathrm{~V}}{\mathrm{R}}\)
- B\(\frac{V}{R}\)
- Correct answerC\(\frac{\mathrm{V}}{2 \mathrm{R}}\)
- D\(\frac{2 \mathrm{~V}}{\mathrm{R}}\)
Solution
Hints: 
\(\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}} \therefore \text { Current in } \mathrm{FC}=\frac{\mathrm{I}}{2}=\frac{\mathrm{V}}{2 \mathrm{R}}\)

\(\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}} \therefore \text { Current in } \mathrm{FC}=\frac{\mathrm{I}}{2}=\frac{\mathrm{V}}{2 \mathrm{R}}\)
Hence, the correct answer is option: 'C'.