Q38 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Chemistry
Find the product of the following reaction, when \(\mathrm{Xe}\) is taken in excess,
\(\mathrm{Xe}(g)+\mathrm{F}_2(g) \longrightarrow \text { ? }\)
- A\(\mathrm{XeF}_4\)
- Correct answerB\(\mathrm{XeF}_2\)
- C\(\mathrm{XeF}_6\)
- D\(\mathrm{XeF}_7\)
Solution
When excess of xenon gas react with fluorine gas at high temperature \((673 \mathrm{~K})\) and 1 bar preesure xenon difluoride \(\left(\mathrm{XeF}_2\right)\) is formed.
\(\mathrm{Xe} \text { (excess) }+\mathrm{F}_2 \xrightarrow{673 \mathrm{~K}, 1 \mathrm{bar}} \mathrm{XeF}_2\)
Hence, the correct option is (b).
Hence, the correct answer is option: 'B'.