Hydrolysis of $\mathrm{XeF}_4$ gives $\mathrm{HF}, \mathrm{O}_2, \mathrm{Xe}$ and ' X '. The structure of ' X ' is

• Correct answer
  A

  pyramidal
• B

  Square pyramidal
• C

  octahedral
• D

  Square planar

Solution

$6 \mathrm{XeF}_4+12 \mathrm{H}_2 \mathrm{O} \longrightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_3+24 \mathrm{HF}+3 \mathrm{O}_2$

Hence, the correct answer is option: 'A'.