Q15 / 150 · MHT CET 2026 (15 April Shift 2) · Chemistry
Find the mass of sodium carbonate in grams to form 100 ml 0.1 M solution in water?
( Molar mass of $\text{Na}_2\text{CO}_3$ = 106 g/mol)
( Molar mass of $\text{Na}_2\text{CO}_3$ = 106 g/mol)
- Correct answerA$1.06$ g
- B$3.18$ g
- C$2.12$ g
- D$4.16$ g
Solution
Molarity is given by the formula:
$M = \dfrac{n}{V \text{ (in L)}}$
Substituting the given values:
$0.1 = \dfrac{n}{0.1}$
$n = 0.01$ moles
Mass of $\text{Na}_2\text{CO}_3$ is calculated as:
$w = n \times \text{Molar mass}$
$w = 0.01 \times 106 = 1.06$ g
Answer: $1.06$ g
$M = \dfrac{n}{V \text{ (in L)}}$
Substituting the given values:
$0.1 = \dfrac{n}{0.1}$
$n = 0.01$ moles
Mass of $\text{Na}_2\text{CO}_3$ is calculated as:
$w = n \times \text{Molar mass}$
$w = 0.01 \times 106 = 1.06$ g
Answer: $1.06$ g
Hence, the correct answer is option: 'A'.