Q18 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Chemistry

Find the correct order of the given elements with respect to their size

  • Correct answer
    A
    \(\mathrm{Zn}>\mathrm{Fe}>\mathrm{Fe}^{2+}>\mathrm{Fe}^{3+}\)
  • B
    \(\mathrm{Fe}^{2+}>\mathrm{Fe}^{2+}>\mathrm{Zn}>\mathrm{Fe}\)
  • C
    \(\mathrm{Fe}>\mathrm{Fe}^{2+}>\mathrm{Fe}^{3+}>\mathrm{Zn}\)
  • D
    \(\mathrm{Zn}>\mathrm{Fe}^{3+}>\mathrm{Fe}^{2+}>\mathrm{Fe}\)

Solution

\(\mathrm{Zn}\) atomic radii is \(137 \mathrm{pm}\) \(\mathrm{Fe}\) atomic radii is \(126 \mathrm{pm}\) \(\mathrm{Fe}^{3+}\) ionic radius is \(63 \mathrm{pm}\), \(\mathrm{Fe}^{2+}\) has an ionic radius of \(77 \mathrm{pm}\). Thus, the correct order of their size is \(\mathrm{Zn} > \mathrm{Fe} > \mathrm{Fe}^{2+} > \mathrm{Fe}^{3+}\) Hence, the correct option is (a).

Hence, the correct answer is option: 'A'.

Relevant Questions