Q17 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Chemistry

A \(40 \%\) by mass sucrose solution is heated till, it becomes \(50 \%\) by mass. Calculate the mass of water lost from \(100 \mathrm{~g}\) of the solution is

  • A
    \(10 \mathrm{~g}\)
  • B
    \(15 \mathrm{~g}\)
  • Correct answer
    C
    \(20 \mathrm{~g}\)
  • D
    \(25 \mathrm{~g}\)

Solution

\(40 \%\) sucrose solution means it contains \(60 \%\) water. After heating, till \(50 \%\) by mass sucrose remains. Thus, \(\%\) water lost \(=\frac{0.4}{0.5} \times 100=80\) Water lost \(=100-80=20 \mathrm{~g}\) Hence, statement (c) is correct.

Hence, the correct answer is option: 'C'.

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