Q134 / 180 · AIIMS 2001 · Physics
Escape velocity of a rocket is $11.2 \mathrm{~km} / \mathrm{sec}$. It is released at an angle of $45^{\circ}$. Its escape velocity is
- A$11.2 \mathrm{~m} / \mathrm{sec}$
- B$11.2 \sqrt{2} \mathrm{~km} / \mathrm{sec}$
- Correct answerC$11.2 \mathrm{~km} / \mathrm{sec}$
- D$22.3 \mathrm{~km} / \mathrm{sec}$.
Solution
The escape velocity is independent of the angle of projection. So, the escape velocity of the rocket remains same.
Hence, the correct answer is option: 'C'.