A satellite is moving with a constant speed $v$ in a circular orbit about the earth. An object of mass $m$ is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is

• A

  $\frac{1}{2} m v^2$
• Correct answer
  B

  $m v^2$
• C

  $\frac{1}{3} m v^2$
• D

  $\frac{2}{3} m v^2$

Hence, the correct answer is option: 'B'.