Q7 / 90 · JEE Main 2019 (09 Apr Shift 2) · Chemistry

During compression of a spring the work done is $10 k J$ and $2 k J$ escaped to the surroundings as heat. The change in internal energy, $Δ U (i n k J)$ is:

A
$- 8$
Correct answer
B
$8$
C
$12$
D
$- 12$

Solution

From the first Law of Thermodynamics,

∆ U = q + W

∆ U = - 2 + 10

q = - 2 k J;

Heat released

W = + 10 k J;

work done on the system

∆ U = 8 k J

Hence, the correct answer is option: 'B'.

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