Q84 / 180 · NEET 2013 (Karnataka) · Chemistry

Crystal field spliting energy for high spin $d^4$ octahedral complex is:

  • A
    $-1.2 \Delta_0$
  • Correct answer
    B
    $-0.6 \Delta_0$
  • C
    $-0.8 \Delta_0$
  • D
    $-1.6 \Delta_0$

Solution

$\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_0$ $x$ is no of $t_{2 \mathrm{~g}}$ orbital while $\mathrm{y}$ is no of $e_g$ orbital $$ \begin{aligned} & =(-0.4 \times 3+0.6 \times 1) \Delta_0 \\ & =-0.6 \Delta_0 \end{aligned} $$

Hence, the correct answer is option: 'B'.

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