The Crystal Field Stabilisation Energy (CFSE) for $\left[\mathrm{CoCl}_6\right]^{4-}$ is $18000 \mathrm{~cm}^{-1}$. The CFSE for $\left[\mathrm{CoCl}_4\right]^{2-}$ will be

• A

  $6000 \mathrm{~cm}^{-1}$
• B

  $16000 \mathrm{~cm}^{-1}$
• C

  $18000 \mathrm{~cm}^{-1}$
• Correct answer
  D

  $8000 \mathrm{~cm}^{-1}$

Hence, the correct answer is option: 'D'.