Q119 / 120 · VITEEE 2018 · Physics

Consider the junction diode as ideal. The value of current flowing through $\mathrm{AB}$ is

  • A
    $0 \mathrm{~A}$
  • Correct answer
    B
    $10^{-2} \mathrm{~A}$
  • C
    $10^{-1} \mathrm{~A}$
  • D
    $10^{-3} \mathrm{~A}$

Solution

Since diode is in forward bias, so the value of current flowing through $\mathrm{AB}$, $\mathrm{i}=\frac{\Delta \mathrm{V}}{\mathrm{R}}=\frac{4-(-6)}{1 \times 10^{3}}=\frac{10}{10^{3}}=10^{-2} \mathrm{~A}$

Hence, the correct answer is option: 'B'.

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