Q105 / 110 · VITEEE 2022 · Physics

A Zener diode has a breakdown voltage of \(9.1 \mathrm{~V}\) with a maximum power dissipation of \(364 \mathrm{~mW}\). What is the maximum current that the diode can withstand ?

  • Correct answer
    A
    \(0.04 \mathrm{~A}\)
  • B
    \(0.4 \mathrm{~A}\)
  • C
    \(4.0 \mathrm{~A}\)
  • D
    \(40 \mathrm{~A}\)

Solution

Applying formula \(\text {Maximum current }=\frac{364 \times 10^{-3}}{9.1}=0.04 \mathrm{~A}\)

Hence, the correct answer is option: 'A'.

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