Consider a matrix $A={\left[a_{ij}\right]}_{3\times 3}$ where, $a_{ij}=\left\{\begin{array}{cc}i+2j& \forall ij=\mathrm{e}\mathrm{v}\mathrm{e}\mathrm{n}\\ 2i-3j& \forall ij=\mathrm{o}\mathrm{d}\mathrm{d}\end{array}\right.$. If $b_{ij}$ is the cofactor of $a_{ij}$ in matrix $A$ and $C_{ij}=\sum _{r=1}^3{a}_{ir}{b}_{jr}$, then ${\left[C_{ij}\right]}_{3\times 3}$ is

• A

  $\left[\begin{array}{ccc}1& 0& 0\\ 0& 1& 0\\ 0& 0& 1\end{array}\right]$
• B

  $\left[\begin{array}{ccc}-1& 5& -7\\ 4& 6& 8\\ 3& 9& -3\end{array}\right]$
• Correct answer
  C

  $\left[\begin{array}{ccc}184& 0& 0\\ 0& 184& 0\\ 0& 0& 184\end{array}\right]$
• D

  $\left[\begin{array}{ccc}2& 3& 1\\ 1& 6& 2\\ -1& 5& 2\end{array}\right]$

Hence, the correct answer is option: 'C'.