Q26 / 59 · NEST (NISER) 2018 · Chemistry

Consider a cyclic process $\mathrm{P} \rightarrow \mathrm{Q} \rightarrow \mathrm{R} \rightarrow \mathrm{P}$ for a system. Among the following, the combination of steps that can never lead to this cyclic process is

  • Correct answer
    A
    $\mathrm{P} \rightarrow \mathrm{Q}:$ Adiabatic irreversible; $\mathrm{Q} \rightarrow \mathrm{R}$ : Adiabatic reversible; $\mathrm{R} \rightarrow \mathrm{P}:$
    Adiabatic reversible
  • B
    $\mathrm{P} \rightarrow \mathrm{Q}$ : Adiabatic irreversible; $\mathrm{Q} \rightarrow \mathrm{R}$ : Adiabatic reversible; $\mathrm{R} \rightarrow \mathrm{P}:$ Isothermal reversible
  • C
    $\mathrm{P} \rightarrow \mathrm{Q}:$ Adiabatic irreversible; $\mathrm{Q} \rightarrow \mathrm{R}$ : Adiabatic reversible; $\mathrm{R} \rightarrow \mathrm{P}:$ Isothermal irreversible
  • D
    $\mathrm{P} \rightarrow \mathrm{Q}$ : Isothermal irreversible; $\mathrm{Q} \rightarrow \mathrm{R}$ : Isothermal reversible; $\mathrm{R} \rightarrow \mathrm{P}:$ Isothermal reversible

Hence, the correct answer is option: 'A'.

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