Q48 / 200 · NEET 2007 · Chemistry

Concentrated of aqueous sulphuric acid is $98 \% \mathrm{H}_2 \mathrm{SO}_4$ by mass and has a density of $1.80 \mathrm{~g} \mathrm{~mL}^{-1}$ Volume of acid required to make one litre of $0.1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ solution is:

  • A
    $16.65 \mathrm{~mL}$
  • B
    $22.20 \mathrm{~mL}$
  • Correct answer
    C
    $5.55 \mathrm{~mL}$
  • D
    $11.10 \mathrm{~mL}$

Solution

Molarity of $\mathrm{H}_2 \mathrm{SO}_4$ solution $=\frac{98 \times 1000}{98 \times 100} \times 1.84=18.4$ Suppose $\mathrm{V} \mathrm{ml}$ of this $\mathrm{H}_2 \mathrm{SO}_4$ is used to prepare 1 . of $0.1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ $\begin{aligned} & \therefore \mathrm{V} \times 18.02=1000 \times 0.1 \\ & \mathrm{~V}=\frac{1000 \times 0.1}{18.02}=5.55 \mathrm{ml} \end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions