Q41 / 180 · NEET 2020 (Phase 1) · Chemistry

Which one of the followings has maximum number of atoms?

Solution

Number of atoms $= \frac{w}{molar mass} \times N_{A} \times atomicity$

Number of atoms in $1 g$ of $Li (s)$ = $\frac{1}{7} \times N_{A} \times 1$

Number of atoms $1 g$ of $Ag$ $(s)$ = $\frac{1}{108} \times N_{A} \times 1$

Number of atoms $1 g$ of $Mg (s)$ = $\frac{1}{24} \times N_{A} \times 1$

Number of atoms $1 g$ of $O_{2} (g)$ = $\frac{1}{32} \times N_{A} \times 2$

Hence, the correct answer is option: 'C'.