Compound ' X ' $\left(\mathrm{C}_4 \mathrm{H}_{11} \mathrm{~N}\right)$ reacts with nitrous acid to form ' Y ' $\left(\mathrm{C}_4 \mathrm{H}_{10} \mathrm{~N}_2 \mathrm{O}\right)$. ' X ' on reaction with an excess of methyl iodide and then with moist silver oxide followed by heating gives trimethyl amine, propene and water. Compound ' X ' is

• Correct answer
  A

  N-Methyl-1-propanamine
• B

  2-Methyl-1-propanamine
• C

  N,N-Dimethylethanamine
• D

  2-Butanamine

Hence, the correct answer is option: 'A'.