$\mathrm{CH} \equiv \mathrm{CH} \frac{\mathrm{HCl}}{\text { Excess }} A \frac{\text { Hydrolysis }}{\Delta} B \frac{\text { Reduction }}{\mathrm{Na}-\mathrm{Hg} / \mathrm{H}_{2} \mathrm{O}} C$ Compound $C$ is

• A

  ethanal
• B

  propenal
• Correct answer
  C

  ethanol
• D

  2-methyl butan-1-ol

Hence, the correct answer is option: 'C'.